How many particle or molecules of Na_2CO_3 are produced when 10g of NaOH is used? 22.3 x 10^24 particles of NaOH are needed to produce how many liters of H_2O? How many particles/molecules of NaOH are from 30 gram of NaOH?

2NaOH(s) + CO_2(g) -> Na_2CO_3(s) + H_2O(l)

1 Answer
Sarthak
Aug 2, 2017

a) 7.5 xx 10^22 molecules of Na_2CO_3 are produced
b)cannot be answered as stoichiometry deals with gases not liquids and water is liquid
c)There are 4.5xx 10^23 molecules of NaOH in 30 g

Explanation:

2NaOH(s) + CO_2(g) -> Na_2CO_3(s) + H_2O(l)

Molar mass of NaOH = 40

2xx40 g of NaOH produces 6.02 xx 10^23 molecules of Na_2CO_3
:. 10 g of NaOH produces (6.02xx10^23xx10)/(2xx40) molecules of Na_2CO_3
= 7.5 xx 10^22 molecules of Na_2CO_3

40g of NaOH contains 6xx10^23 molecules
:. 30g of NaOH contains (30xx6xx10^23)/40 molecules
=4.5xx10^23 molecules

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