How many Oxygen atoms in 1.44 x 10^5 kg of Nitrogen Oxide?

1 Answer
anor277
Jul 17, 2017

Well, I will do it for NO_2(g)........and get over six million moles......

Explanation:

But of course there is NO and N_2O.........

For NO_2, we have a molecular mass of 46.01*g*mol^-1.

And thus "Moles of" NO_2 = (1.44xx10^8*g)/(46.01*g*mol^-1)

-=3.13xx10^6*mol....and thus 6.26xx10^6*mol "oxygen atoms."

Then, you continue to solve for the number of oxygen atoms.

6.26xx10^6*molxx6.022 * 10^23*mol^-1~= 4.0xx10^30 "oxygen atoms" which is nearer to the given answer.

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