How many neutrons are present in a stable atom of #Ag#?

Redirected from "Suppose that I don't have a formula for #g(x)# but I know that #g(1) = 3# and #g'(x) = sqrt(x^2+15)# for all x. How do I use a linear approximation to estimate #g(0.9)# and #g(1.1)#?"
1 Answer
Jul 4, 2016

60 or 62 neutrons.

Explanation:

There are two stable isotops of silver (Ag):

  • Ag-107: 47 protons and 60 neutrons #-> "_47^107Ag#
  • Ag-109: 47 protons and 62 neutrons #-> "_47^109Ag#

52% of the stable Ag-isotopes is #"^107Ag#, 48% is #"^109Ag#.