How many moles of sodium carbonate contain 1.773 xx 10^17 carbon atoms?

1 Answer
Nov 12, 2016

If we want 1.773xx10^17 "C" atoms in "Na"_2"CO"_3, then we can define our own ratio of:

"1 mol C" = "1 mol Na"_2"CO"_3

Therefore:

color(blue)(1.773xx10^17 "C atoms") xx ("1 mol C")/(6.022xx10^23 "C atoms") xx ("1 mol Na"_2"CO"_3)/("1 mol C")

= color(blue)(2.944xx10^(-7) "mols Na"_2"CO"_3)