How many moles of nitrogen gas will occupy a volume of 347 mL at 6680 mmHg and 27 #"^o#C?

1 Answer
anor277
Nov 29, 2016

#6680*mm*Hg# is not a realistic measurement of pressure....

Explanation:

I assume you mean #(6680*mm*Hg)/(760*mm*Hg*atm^-1)=8.79*atm#.

And we use the Ideal Gas Equation:

#n=(PV)/(RT)=(8.79*atmxx0.347*L)/(0.0821*L*atm*K^-1*mol^-1xx300*K)=0.124*mol#

What is the mass of the quantity of nitrogen gas?

Related questions
See all questions in Mole Ratios
Impact of this question
10816 views around the world
You can reuse this answer
Creative Commons License