How many moles of $N a C l$ $NaCl$ are present in 20.0 g of $N a C l$ $NaCl$ ?

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Answer 1 · 2018-04-20T07:32:27

$0.342 mol$ $"0.342 mol"$

Molar mass of $NaCl = 58.4 g/mol$ $"NaCl = 58.4 g/mol"$

Number of moles in $20.0 g NaCl$ $"20.0 g NaCl"$ is

$(20.0 cancel"g")/(58.4 cancel"g""/mol") = "0.342 mol"$

How many moles of NaClNaClNaCl are present in 20.0 g of NaClNaClNaCl?