How many moles of magnesium, chlorine, and oxygen atoms are there in 7.50 moles of magnesium perchlorate, $"Mg"("ClO"_4)_2$ ?

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Answer 1 · 2015-11-09T07:00:50

$"7.50 mol Mg"("ClO"_4)_2$ contains:

$"7.50 mol Mg atoms"$
$"15.0 mol Cl atoms"$
$"60.0 mol O atoms"$

$"1 mol Mg(ClO"_4)_2"$ contains $"1 mol Mg atoms", "2 mol Cl atoms", and "8 mol O atoms"$ .

To determine the number of moles of each element in $"7.50 mol"$ of the compound, multiply the moles of each element times $"7.50"$ .

$7.50cancel("Mg"("ClO"_4)_2)xx(1"mol Mg atoms")/(1cancel("mol Mg"("ClO"_4)_2))="7.50 mol Mg atoms"$

$7.50cancel("mol Mg"("ClO"_4)_2)xx(2"mol Cl atoms")/(1cancel("mol Mg"("ClO"_4)_2))="15.0 mol Cl atoms"$

$7.50cancel("mol Mg"("ClO"_4)_2)xx(8"mol O atoms")/(1cancel("mol Mg"("ClO"_4)_2))="60.0 mol O atoms"$

How many moles of magnesium, chlorine, and oxygen atoms are there in 7.50 moles of magnesium perchlorate, "Mg"("ClO"_4)_2"Mg"("ClO"_4)_2?