How many moles of $K C l$ $KCl$ are produced from 2.50 moles of $K$ $K$ and excess $C l_{2}$ $Cl_2$ ?

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Answer 1 · 2018-01-11T14:11:29

$2.5$ $2.5$

The reaction is
$2 K + C l_{2} = 2 K C l$ $2K + Cl_2 = 2KCl$
Thus the number of moles of potassium and potassium chloride is same

How many moles of KClKCl are produced from 2.50 moles of KK and excess Cl2Cl_2?