How many moles of KCI are present in 189 mL of a 0.745 M solution?

1 Answer
anor277
Nov 25, 2016

Approx. #0.15*mol..........#

Explanation:

#"Concentration"="Moles of solute"/"Volume of solution"#

To get one quantity or the other, we take the quotient or the appropriate product.

Adn thus #"Moles of solute"="Concentration"xx"Volume of solution"#

#=0.745*mol*cancel(L^-1)xx189*cancel(mL)xx10^-3cancelL*cancel(mL^-1)=??*mol.#

And thus the calculation was dimensionally consistent.

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