How many moles of H_2SO_4 are present in half a liter of a 0.150 M H_2SO_4 solution?

1 Answer
anor277
May 12, 2017

0.075*mol

Explanation:

"Molarity"="Moles of solute"/"Volume of solution"

And thus, "Moles of solute"="Volume of solution"xx"molarity"

=0.5*Lxx0.150*mol*L^-1=0.075*mol with respect to H_2SO_4.

Of course, we speak of a formal concentration. We know that in aqueous solution sulfuric acid speciates to give HSO_4^- and SO_4^(2-), and equivalent quantities of H_3O^+.

Related questions
See all questions in The Mole
Impact of this question
1305 views around the world
You can reuse this answer
Creative Commons License