How many moles of compound are there in 4.5 kg $Ca(OH)_2$ ?

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Answer 1 · 2016-02-08T03:44:29

$"4.5 kg Ca(OH)"_2"$ contains $"61 moles"$ .

Determine Moles of Calcium Hydoroxide

You will need to divide the given mass by the molar mass of $"Ca(OH)"_2"$ .

The molar mass of calcium hydroxide, $"Ca(OH)"_2"$ is $"74.09268 g/mol"$ . https://pubchem.ncbi.nlm.nih.gov/compound/6093208

Since molar mass is given in g/mol, 4.5 kg needs to be converted to grams.

Convert kg to grams.

$4.5cancel"kg"xx(1000"g")/(1cancel"kg")="4500 g"$

Determine the moles of calcium hydroxide contained in $"4500 g Ca(OH)"_2"$ by dividing the given mass by its molar mass.

$4500cancel"g Ca(OH)"_2xx(1"mol Ca(OH)"_2)/(74.09268 cancel"g Ca(OH)"_2)="61 mol Ca(OH)"_2"$ (rounded to two significant figures)

How many moles of compound are there in 4.5 kg Ca(OH)_2Ca(OH)_2?