How many moles of chlorine gas will be required to react with sufficient iron to produce 14 moles of iron (III) chloride?

Question

$2Fe(s) + 3Cl_2(g) -> 2FeCl_3(g)$

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Answer 1 · 2017-01-26T23:17:53

The reaction is $2Fe+3Cl_2->2FeCl_3$

So the mol ratio $Cl_2divFeCl_3=3div2$

So for 14 mols of $FeCl_3$ we need $3/2xx14=21$ mols of $Cl_2$