How many moles of $C a B r_{2}$ $CaBr_2$ are in 5.0 grams of $C a B r_{2}$ $CaBr_2$ ?

Question

24546 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-19T05:48:59

0.25 mol

Molar mass of Calcium Bromide is 200 g $m o l^{- 1}$ $mol^-1$

Mass of Calcium Bromide = 5.0 g

moles of Ca $B r_{2}$ $Br_2$ = mass of Ca $B r_{2}$ $Br_2$ / molar mass of Ca $B r_{2}$ $Br_2$

moles of Ca $B r_{2}$ $Br_2$ = 5.0 g / 200 g $m o l^{- 1}$ $mol^-1$

moles of Ca $B r_{2}$ $Br_2$ = 0.25 mol

How many moles of CaBr_2CaBr2CaBr_2 are in 5.0 grams of CaBr_2CaBr2CaBr_2?