How many moles of barium hydroxide, #Ba(OH)_2# would be required to react with 117g hydrogen bromide, #HBr# in the reaction #2HBr + Ba(OH)_2 -> BaBr_2 + 2H_2O#?
1 Answer
Apr 10, 2016
Approx. 0.725 moles of
Explanation:
Moles of
The stoichiometry of the reaction explicitly tells us that each mole, each equivalent, of barium hydroxide requires 2 mole, 2 equivalents, of hydrogen bromide.
Thus
