How many moles of aluminum, sulfur, and oxygen atoms are there in 7.00 moles of aluminum sulfate, Al_2(SO_4)_3Al2(SO4)3?

1 Answer
Meave60
Nov 12, 2015

7.007.00 moles of "Al"_2("SO"_4)_3"Al2(SO4)3 contain 14.014.0 mol Al atoms, 21.021.0 mol S atoms, and 84.084.0 mol O atoms.

Explanation:

In one mole of aluminum sulfate, "Al"_2"(SO"_4")"_3"Al2(SO4)3, there are 2 moles Al atoms, 3 moles sulfur atoms, and 12 moles O atoms.

To determine the number of moles of atoms of each element in 7.00 moles of the compound, multiply the number of moles times 7.00.

"Al":Al:7.00cancel("mol Al"_2("SO"_4)_3)xx(2"mol Al atoms")/(1cancel("mol Al"_2("SO"_4)_3))="14.0 mol Al atoms"

"S":7.00cancel("mol Al"_2("SO"_4)_3)xx(3"mol S atoms")/(1cancel("mol Al"_2("SO"_4)_3))="21.0 mol S atoms"

"O":7.00cancel("mol Al"_2("SO"_4)_3)xx(12"mol O atoms")/(1cancel("mol Al"_2("SO"_4)_3))="84.0 mol O atoms"

Related questions
See all questions in The Mole
Impact of this question
96193 views around the world
You can reuse this answer
Creative Commons License