How many moles are present in 32.5 g aluminum chloride?

1 Answer
Sep 28, 2016

"Moles of aluminum chloride "=" approx. 0.250 moles"

Explanation:

"Moles" = "Mass of compound"/"Molar mass of compound"

= (32.5*g)/((26.98+3xx35.45)*g*mol^-1)

= (32.5*g)/(133.33*g*mol^-1) = ??" moles".