How many moles are in $3.45 * 10^24$ molecules of calcium iodide?

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Answer 1 · 2016-02-10T19:23:49

In $1$ mole of $CaI_2$ , there are $6.022xx10^23$ formula units of $CaI_2$ .

So, moles of $CaI_2$ $=$ $(3.45xx10^24)/(6.022xx10^23*mol^-1)$ $~=$ $6$ $"moles"$ .

How many moles of iodine atoms are in this molar quantity?

How many moles are in 3.45 * 10^243.45 * 10^24 molecules of calcium iodide?