How many moles are equivalent to 3.58 * 10^23 formula units of ZnCl_2?

1 Answer
anor277
Feb 2, 2016

Approx. 0.60 moles of ZnCl_2.

Explanation:

In one mole of ZnCl_2 there are 6.022xx10^23 formula units; i.e. 6.022xx10^23 INDIVIDUAL zinc atoms, and 2xx6.022xx10^23 INDIVIDUAL chlorine atoms.

Now the mass of one mole of ZnCl_2 is 136.32 g. What is the mass of 3.58xx10^23 formula units of ZnCl_2?

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