How many moles are equal to $2.69 \cdot 10^{78}$ $2.69 * 10^78$ atoms of sulfur?

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How many moles are equal to $2.69 \cdot 10^{78}$ $2.69 * 10^78$ atoms of sulfur?

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Answer 1 · 2016-03-31T20:43:02

$4.47 \times 10^{54}$ $4.47xx10^54$ moles

Explanation:

How many dozens is 72? you just need to divide 72 by 12.

With mols it is exactly the same thing.
1 mol is approximately $6.022 \times 10^{23}$ $6.022xx10^23$ , so you must divide the given number by $6.022 \times 10^{23}$ $6.022xx10^23$ :

$\frac{2.69 \times 10^{78}}{6.022 \times 10^{23}} = 4.47 \times 10^{54}$ $(2.69xx10^78)/ (6.022xx10^23)=4.47xx10^54$

Since the molar mass of Sulfur is about 32.06 g/mol you will get:

$4.47 \times 10^{54} \times 32.06 \times 10^{- 3} = 1.43 \times 10^{53} k g$ $4.47xx10^54xx32.06xx10^(-3)=1.43xx10^53 kg$

This number is extraordinarly huge. It is comparable with the mass of the whole Universe, which it's taken as being at least $10^{53} k g$ $10^53 kg$

https://en.wikipedia.org/wiki/Universe

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How many moles are equal to $2.69 \cdot 10^{78}$ $2.69 * 10^78$ atoms of sulfur?

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