How many molecules of NH_3 are produced from 4.82*10^-4 g of H_2?

1 Answer
Dr. Hayek
Feb 27, 2016

9.58xx10^(19)"molecules"NH_3

Explanation:

The reaction of making NH_3 from H_2 is the following:

3H_2(g)+N_2(g)->2NH_3(g)

Therefore, using dimensional analysis, we can use the molar ratio from the balanced equation to find the number of molecules of NH_3 produced by:

?"molecules"NH_3=4.82xx10^(-4)cancel(gH_2)xx(1cancel(molH_2))/(2.02cancel(gH_2))xx(2cancel(molNH_3))/(3cancel(molH_2))xx(6.022xx10^(23)"molecules"NH_3)/(1cancel(molNH_3))=9.58xx10^(19)"molecules"NH_3

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