How many molecules are there in 8.8 grams of $SO_2$ ?

Question

5724 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-14T04:51:52

Approx. $8.3xx10^22*"molecules of"$ $SO_2,$

We (i) calculate the equivalent quantity of sulfur dioxide to get an answer in moles:

$"Moles of sulfur dioxide"$ $=$ $(8.8)/(64.07*g*mol^-1)~=1/8*mol$ .

Then (ii) convert this molar quantity into a number of particles, knowing that $1*mol-=N_A$ $"particles"$ :

$~=6.022xx10^23*mol^-1xx1/8*mol=??"molecules........."$

How many molecules are there in 8.8 grams of SO_2SO_2?