How many molecules are there in 237 grams of #"CCl"_4#?

1 Answer
Phiri · Meave60
May 16, 2018

#9.28 * 10^23# molecules of #C"Cl_4#

Explanation:

Using stoichiometry, we need to convert grams of #(C"Cl_4)# to moles, then moles to molecules.

#237color(red)cancel(color(black)("g")) * (1color(red)cancel(color(black)("mol")))/(153.82color(red)cancel(color(black)("g"))) * (6.02*10^23"molecules")/(1color(red)cancel(color(black)("mol"))) = 9.28 * 10^23"# #"molecules"#

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