How many molecules are in 72.00 g of $C_6H_12O_6$ ?

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Answer 1 · 2016-03-29T19:02:39

$0.400xxN_A$ , where $N_A$ $=$ $"Avogadro's number"$

Given that there are $72.00$ $g$ , this represents a molar quantity of $(72.00*cancelg)/(180.16*cancelg*mol^-1)$ $=$ $0.400$ $mol$ .

We simply multiply this molar quantity by $N_A" Avogadro's number"$ :

$0.400*molxx6.022xx10^23*mol^-1$ $=$ $??$

How many molecules are in 72.00 g of C_6H_12O_6C_6H_12O_6?