How many mL of a .10 M $NaOH$ solution are needed to neutralize 15 mL of .20 M $H_3PO_4$ solution?

Question

29684 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-19T21:48:58

30 mL

Use the formula $M_AV_A = M_BV_B$ .

$M_A =$ Molarity of acid, $V_A =$ Volume of acid
$M_B =$ Molarity of base, $V_B =$ Volume of base

1. Plug known values into the formula.

$(.20)(15) = .10(x)$

2. Solve for x.

$3 = .10x$
$x = 30$

30 mL is your answer.

How many mL of a .10 M NaOHNaOH solution are needed to neutralize 15 mL of .20 M H_3PO_4H_3PO_4 solution?