How many milliliters of 0.200M $NaOH$ solution are needed to react with 22.0 mL of a 0.490 M $NiCl_2$ solution?

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Answer 1 · 2015-12-08T18:02:32

There are $0.0108$ $mol$ $NiCl_2$ . $0.0216$ $mol$ $NaOH$ are required, given $0.200$ $mol*L^-1$ $NaOH(aq)$ .

$NiCl_2(aq) + 2NaOH(aq) rarr Ni(OH)_2(s)darr + 2NaCl(aq)$

There are $0.0108$ $mol$ $NiCl_2$ ( $22.0xx10^(-3)cancelLxx0.490*mol*cancel(L^-1)$ ). So, by stoichiometry $0.0216$ $mol$ $NaOH$ are required.

There is $0.200$ $mol*L^-1$ $NaOH$ solution available, so...

$(0.0216*cancel(mol))/(0.200*cancel(mol)*cancel(L^-1))xx1000*mL*cancel(L^-1)$ $=$ $?? mL$

How many milliliters of 0.200M NaOHNaOH solution are needed to react with 22.0 mL of a 0.490 M NiCl_2NiCl_2 solution?