How many liters of oxygen are needed to burn 10 liters of carbon monoxide?

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How many liters of oxygen are needed to burn 10 liters of carbon monoxide?

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Answer 1 · 2018-03-27T05:33:10

$C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g)$ $CO(g) + 1/2O_2(g) rarr CO_2(g)$

Explanation:

WE have the stoichiometric equation....but at constant temperature, and constant pressure (and we must ASSUME these conditions pertain)... $V \propto n$ $Vpropn$ ,,this can be seen from the old Ideal Gas equation... $P V = n R T$ $PV=nRT$ ..and is explicitly stated in old Avogadro's gas law.

And so if there is a $10 \cdot L$ $10*L$ volume of carbon monoxide, a $5 \cdot L$ $5*L$ volume of dioxygen contains a stoichiometric equivalent.

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How many liters of oxygen are needed to burn 10 liters of carbon monoxide?

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