How many liters do #3.60xx10^(24)# molecules of #"O"_2# occupy at STP?

1 Answer
anor277
May 28, 2017

The #"molar volume at STP"# is #22.4*L#......And thus there are approx. #134*L# of oxygen gas........

Explanation:

So to address your question, we (i) work out the molar quantity of #"dioxygen gas......."#

#"Moles of dioxygen"# #=# #(3.60xx10^24*"molecules")/(6.022xx10^23*"molecules"*mol^-1)# #=# #6.0*mol.#

And then (ii) we take the product:

#6.0*cancel(mol)xx22.4*L*cancel(mol^-1)=??#

@Kathryn, the formatting here is sometimes infuriating.....you are not the only person to find it difficult.

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