How many liters are contained in 1.75 mol of F2 gas at STP?

1 Answer
Stefan V.
Dec 7, 2014

The answer is #39.2L#.

The gas laws tell us that all ideal gasses behave identically under the same conditions. At STP, the molar volume of any ideal gas is equal to #V_(mol ar) = 22.4L#, which means that #1# mole of any gas at STP will occupy exactly #22.4 L#.

Therefore we can determine the volume occupied by any number of moles of any ideal gas at STP by using

#n = V/V_(mol ar)#, which results in #V = n * V_(mol ar) = 1.75 mo l es* (22.4 L)/(1 mol e) = 39.2 L#

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