How many ions are there in a solution with 9.656 mol of $Ni^(2+)$ ?

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How many ions are there in a solution with 9.656 mol of $Ni^(2+)$ ?

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Answer 1 · 2016-03-08T18:04:08

Clearly there are $9.656$ $mol$ of $Ni^(2+)$ . But $Ni^(2+)$ is not the only ion present.

Explanation:

How do I know this? Because $Ni^(2+)$ must have a counterion. This could have been halide, or nitrate, or acetate, or something else.

The number of $Ni^(2+)$ ions is $N_A$ $xx$ $9.656$ $mol$ . $N_A$ is Avogadro's number $=$ $6.022xx10^23*mol^-1$ . So the number of ions is rather large.

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How many ions are there in a solution with 9.656 mol of $Ni^(2+)$ ?

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How many ions are there in a solution with 9.656 mol of Ni^(2+)Ni^(2+)?

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Explanation:

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How many ions are there in a solution with 9.656 mol of $Ni^(2+)$ ?