How many ions are there in 4.5 g of (NH_4)_3PO_4?

1 Answer
anor277
May 4, 2016

Approx. 0.121*mol of phosphate and ammonium ions.

Explanation:

The formula mass of ammonium phosphate is 149.09*g*mol^-1. A mass of 4.5*g corresponds to a molar quantity of (4.5*g)/(149.09*g*mol^-1) = 3.02xx10^(-2)*mol with respect to (NH_4)_3PO_4, and thus 3.02xx10^(-2)xx4=0.121*mol of ions, given that there are 4 individual ion per formula unit of ammonium phosphate.

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