How many hours will a car traveling at 75 miles per hour take to catch up to a car traveling at 55 miles per hour if the slower car starts two hours before the faster car?

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Answer 1 · 2014-11-24T14:55:42

Let $x$ $x$ be the time required for the faster car to catch up to the slower car.

Catch up means the distance traveled by both cars are equal.

$75 x = 55 (x + 2)$ $75x = 55(x + 2)$

$\Rightarrow 75 x = 55 x + 110$ $=> 75x = 55x + 110$

$\Rightarrow 75 x - 55 x = 110$ $=> 75x - 55x = 110$

$\Rightarrow 20 x = 110$ $=> 20x = 110$

$\Rightarrow x = 5.5$ $=> x = 5.5$