How many grams of gold should a coin of 35% gold be if when combined with a 3 grams pure gold necklace, it forms a metal that is 69 % gold?
1 Answer
Here's what I got.
Explanation:
Since I'm not sure if you're asking for the mass of the
So, let's say that the coin that is
#x color(red)(cancel(color(black)("g coin"))) * "35 g gold"/(100color(red)(cancel(color(black)("g coin")))) = 35/100x " g gold"#
Now let's say that the mass of the
#y color(red)(cancel(color(black)("g coin"))) * "69 g gold"/(100color(red)(cancel(color(black)("g coin")))) = 69/100y" g gold"#
Now, use the
#x + 3 = y#
and
#35/100x + 3 = 69/100y#
Use the first equation to get
#x = y - 3#
Plug this into the second equation to get
#35/100 * (y - 3) + 3 = 69/100y#
#35/100y - 105/100 + 3 = 69/100y#
This is equivalent to
#(35 - 69)/100 * y = -195/100#
#34y = 195 implies y = 5.74#
This means that
#x = 5.74 - 3 = 2.74#
So, if you start with a
The first coin will contain
#2.74 color(red)(cancel(color(black)("g coin"))) * "35 g gold"/(100color(red)(cancel(color(black)("g coin")))) = "0.959 g gold"#
I'll leave the values rounded to three sig figs, despite the fact that your values would only justify one sig fig.