How many grams of fluorine gas will exert a pressure of 1.54 atm in a 3.2-liter container at 40 °C?

1 Answer
anor277
May 8, 2017

You MUST know that elemental fluorine is the gaseous F_2 molecule.

Explanation:

And in fact all the elemental gases, save for the Noble Gases, are bimolecular species. Is this true?

And we use the Ideal Gas Equation:

PV=nRT="mass"/"molar mass"xxRT

And thus "mass"=(PVxx"molar mass")/(RT)

And we plugs in the numbers:

(1.54*atmxx3.2*Lxx38.0*g*mol^-1)/(0.0821*(L*atm)/(K*mol)xx313.1*K)=

7.29*g.

Remember what I said with regard to the so-called molecularity of elemental gases. And fluorine gas, the most reactive substance on the Periodic Table, is not to be handled without special precautions.

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