How many grams of CH_4CH4 are present in 5.14*10^235.14⋅1023 molecules of CH_4CH4?

1 Answer
anor277
Aug 15, 2016

Well, 6.022xx10^236.022×1023 methane molecules have a mass of 16.01*g16.01⋅g.

Explanation:

So,

(5.14xx10^23*"methane molecules")/(6.022xx10^23*"methane molecules mol"^-1)xx16.01*g*mol^-15.14×1023⋅methane molecules6.022×1023⋅methane molecules mol−1×16.01⋅g⋅mol−1

~=≅ 13*g13⋅g

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