How many grams are in 4.5 x 1028 moles of sodium fluoride, NaF?

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Answer 1 · 2018-02-20T04:04:37

I get around $3139542 \ "g"$ .

I think your question is,

How many grams are in $4.5 xx 10^28$ molecules of sodium fluoride, $NaF$ ?

That's because if you talk about $4.5 x 1028$ moles of sodium fluoride, you would get a really absurd number of grams.

So, I'd solve your problem assuming your question is How many grams are in $4.5 xx 10^28$ molecules of sodium fluoride, $NaF$ ?.

In that, we first have to convert the amount of molecules into moles.

We know that $1 \ "mol" = 6.02*10^23$ molecules, so in here, we get

$(4.5*10^28cancel"molecules")/(6.02*10^23cancel"molecules""/mol")=74750.8306~~74751 \ "mol"$

Sodium fluoride has a molar mass of $42 \ "g/mol"$ . So, the mass of $74751$ moles of sodium fluoride will be

$42"g/"cancel"mol"*74751cancel"mol"=3139542 \ "g"$