How many grams are contained in 3.22 moles of dinitrogen tetroxide?

2 Answers
P dilip_k
Apr 23, 2016

Molar mass of N_2O_3=2xx14+3xx16=76gmol^-1
Mass of 3.22 moles of N_2O_3=3.22molesxx76g/(mol)=244.72g

Edmund Liew
May 1, 2016

The formula for dinitrogen tetroxide is N_2O_4.

Assume that:
n - number of moles
m - mass of substance
M - molar mass

n = m -: M

3.22 moles (n) of N_2O_4 has been provided for you.

Next step is to find out the molar mass (M). Before that, break up the formula, first, to make sure that you know what atoms are present. You can see that Nitrogen and Oxygen are present. If you refer to your periodic table, the molar mass of Nitrogen is 14.0 g/mol and Oxygen 16.0 g/mol.

Therefore, the molar mass (M) of dinitrogen tetroxide is:
[2 xx 14.0 + 4 xx 16.0] = 92.0 g/mol.

Your last step is to find out the mass.
Look back at the n = m -: M formula and make m as the subject. Flip it over and it'll become m = M xx n.

The mass of N_2O_4 is:
[m = 92.0 g/mol xx 3.22 moles] = 296.2 grams.
Note that this answer is rounded to 3 significant figures.

Overall, 296.2 grams are contained in 3.22 moles of dinitrogen tetroxide.

Related questions
See all questions in The Mole
Impact of this question
17288 views around the world
You can reuse this answer
Creative Commons License