How many formula units are contained in 1.34g $CaO$ ?

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Answer 1 · 2016-03-07T13:08:31

$(1.34*g)/(74.10*g*mol^-1)$ $xx$ $N_A$ , where $N_A$ $=$ $"Avogadro's number"$

There are $(1.34*g)/(74.10*g*mol^-1)$ $=$ $?? " moles calcium hydride"$ .

Now, it is a fact that $1$ $"mole"$ of stuff, there are $6.022xx10^23$ individual items of that stuff.

You have $0.0181$ $mol$ . Therefore:

$0.0181$ $mol$ $xx$ $6.022xx10^23*mol^-1$ $=$ $??" formula units of calcium hydroxide"$ .

How many formula units are contained in 1.34g CaOCaO?