How many $C O_{2}$ $CO_2$ molecules are in $1.70 \cdot 10^{- 2}$ $1.70 * 10^-2$ mole of $C O_{2}$ $CO_2$ ?

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How many $C O_{2}$ $CO_2$ molecules are in $1.70 \cdot 10^{- 2}$ $1.70 * 10^-2$ mole of $C O_{2}$ $CO_2$ ?

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Answer 1 · 2016-12-12T17:56:10

There are $1.70 \times 10^{- 2} \cdot m o l \times N_{A}$ $1.70xx10^-2*molxxN_A$ $C O_{2}$ $CO_2$ molecules, where.......

Explanation:

.......where $N_{A} = Avogadro's Number$ $N_A="Avogadro's Number"$ $=$ $=$ $6.022 \times 10^{23} \cdot m o l^{- 1}$ $6.022xx10^23*mol^-1$ .

And so, $1.70xx10^-2*molxxN_A=1.70xx10^-2*cancel(mol)xx6.022xx10^23*cancel(mol^-1)$ , approx. $1.0xx10^22$ $"carbon dioxide molecules"$ . We get the answer as a number as required.

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How many $C O_{2}$ $CO_2$ molecules are in $1.70 \cdot 10^{- 2}$ $1.70 * 10^-2$ mole of $C O_{2}$ $CO_2$ ?

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How many CO_2CO2CO_2 molecules are in 1.70 * 10^-21.70⋅10−21.70 * 10^-2 mole of CO_2CO2CO_2?

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How many $C O_{2}$ $CO_2$ molecules are in $1.70 \cdot 10^{- 2}$ $1.70 * 10^-2$ mole of $C O_{2}$ $CO_2$ ?