How many carbon atoms are present in 0.52 moles of C2H6O?
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"A 5.00 L sample of helium at STP expands to 15.0 L. What is the new pressure on the gas?"
....a #1.04*mol# quantity....
By definition, a mole specifies #6.022xx10^23# individual particles of stuff. And we use this number because #6.022xx10^23# individual #""^1H# atoms have a mass of #1.00*g# precisely. The mole is thus the link between the micro world of atoms and molecules to the macro world of grams, and litres.
Here we gots a #0.52*mol# quantity of #C_2H_6O#...we gots #0.52*molxx6.022xx10^23*mol^-1# #"oxygen atoms"#, #
2xx0.52*molxx6.022xx10^23*mol^-1# #"carbon atoms"#, and #6xx0.52*molxx6.022xx10^23*mol^-1# #"hydrogen atoms"#.
Note that here we use the mole precisely as we would use other collective numbers, i.e. #"dozen"#, #"score"#, #"gross"#. How do find the masses of each of the elemental quantities?