How many atoms or molecules are present in 1.0 mol of Au? How am I able to find the answer?

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How many atoms or molecules are present in 1.0 mol of Au? How am I able to find the answer?

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Answer 1 · 2015-05-11T20:02:44

You use the fact that 1 mole of any substance contains exactly $6.022 \cdot 10^{23}$ $6.022 * 10^(23)$ atoms or molecules of that substance - this is known as Avogadro's number.

![https://shirleycahyadi.wordpress.com/2013/09/30/different-formulas-for-quantitative-chemistry-and-mole-conversion/]( useruploads.socratic.org )

In your case, 1 mole of gold will have exactly $6.022 \cdot 10^{23}$ $6.022 * 10^(23)$ atoms of gold.

$1.0 mole \cdot \frac{6.022 \cdot 10^{23} atoms}{1 mole} = 6.022 \cdot 10^{23} atoms of Au$ $1.0cancel("mole") * (6.022 * 10^(23)"atoms")/(1cancel("mole")) = 6.022 * 10^(23)"atoms of Au"$

If round the answer to two sig figs, the number of sig figs in 1.0, you'll get

$1.0 mole Au = 6.0 \cdot 10^{23} atoms Au$ $"1.0 mole Au" = color(green)(6.0 * 10^(23)"atoms Au")$

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How many atoms or molecules are present in 1.0 mol of Au? How am I able to find the answer?

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