How many atoms of copper are contained in 5.25 moles?

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How many atoms of copper are contained in 5.25 moles?

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Answer 1 · 2017-01-24T18:17:02

$5.25 \times N_{A}$ $5.25xxN_A$ ........

Explanation:

$5.25 \times N_{A}$ $5.25xxN_A$ ........where $N_{A} \equiv Avogadro's number, 6.022 \times 10^{23} \cdot m o l^{- 1}$ $N_A-="Avogadro's number, " 6.022xx10^23*mol^-1$

And thus $5.25 \cdot m o l$ $5.25*mol$ copper atoms containes over $30 \times 10^{23}$ $30xx10^23$ inidividual copper atoms. This is clear dimensionally,

$5.25*cancel(mol)xx6.022xx10^23*cancel(mol^-1)=??$

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How many atoms of copper are contained in 5.25 moles?

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