How many atoms are present in 95.1 L H_2O at STP?

1 Answer
anor277
Feb 6, 2016

You should tell us. What is the state of water at STP?

Explanation:

There are 95.1 kg of water at STP; i.e (95.1xx10^3*g)/(18.01*g*mol^-1) = ?? "moles".

Now the mole represents Avogadro's number of particles, 6.022xx10^23 mol^-1, N_A. So multiply the number of moles first by N_A to give the number water molecules, and then mulitply this quantity by 3. Why three?

Because this is a large number, you would be justified in using the symbol N_A in your answer, provided you defined it.

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