How many atoms are in 3.5 moles of arsenic atoms?

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Answer 1 · 2018-03-20T01:14:12

See below
$2.1xx10^24 "atoms As"$

$3.5 cancel"mol As"* (6.02*10^23 "atoms As")/(1 cancel"mol As")=$

$2.1xx10^24 "atoms As"$

Answer 2 · 2018-03-20T01:15:49

$2.11 × 10^24\ "Arsenic atoms"$

$"1 mol of atoms" = 6.022 × 10^23\ "atoms"$

$3.5 cancel"mol" × (6.022 × 10^23\ "atoms")/(1 cancel"mol") = 2.11 × 10^24\ "atoms"$