How many atoms are contained in 0.55 moles of Br?

1 Answer
Apr 12, 2017

0.55xxN_A "bromine atoms.........."

Explanation:

Where N_A="Avogadro's Number," 6.022xx10^23*mol^-1.

And thus, 0.55*cancel(mol)xx6.022xx10^23*cancel(mol^-1)=3.31xx10^23 "bromine ATOMS".

Note that here we use the mole as would use any other collective term, i.e. dozen, score, gross............Of course the mole specifies a much larger quantity of stuff.

Also note that we specify a quantity of 0.55 mol "bromine atoms". A quantity of 0.55 mol "bromine molecules" would contain TWICE this number of bromine atoms. Why?