How liters of 1.5 M #HCl# solution would react completely with 25 moles #Ca(OH)_2#?

Question

2434 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-06T13:18:48

Just over 33 litres

First write the balanced equation:

#Ca(OH)_2 (s) + 2HCl (aq) -> CaCl_2 (aq) + 2H_2 O (l)#

From this you can see that each mole of calcium hydroxide reacts with 2 moles of hydrochloric acid.

You have 25 moles of calcium hydroxide, so it means that 50 moles of hydrochloric acid is required.

The molarity of the hydrochloric acid is 1.5 M, and

#"number of litres" = "number of moles"/"molarity"#

This is

#"50 moles"/"1.5 mol/L" = "33.3 litres"#