How is the pH of a solution related to the #[H_3O^+]#?

1 Answer
anor277
Jun 23, 2016

#pH=-log_10[H_3O^+]#

Explanation:

So given a neutral solution, #[H_3O^+][HO^-]=10^(-14)#, and since, by definition, #[H_3O^+]=[""^(-)OH]#, i,e,. #[H_3O^+]# #=# #10^-7*mol*L^-1#

And thus #pH# #=# #-log_10(10^-7)# #=# #7# (because #log_(a)a^b# #=# #b# by definition). You might need to review the logarithmic function.

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