How is the following solved? Is there reciprocation?
#(a/b+c/d) divide (a/b-c/d) #
1 Answer
May 11, 2018
Explanation:
#"simplify each factor"#
#rArr(ad+bc)/(bd)" and "(ad-bc)/(bd)#
#"change "-:" to "xx" and invert second fraction"#
#rArr(ad+bc)/cancel(bd)xxcancel(bd)/(ad-bc)=(ad+bc)/(ad-bc)#
