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How i calculate the value of the sum $2^(n+3)/(n!)$ ?

1 Answer

Jun 18, 2016

$2^3e^2$

Explanation:

$e^x = sum_{i=0}^{oo}x^i/(i!)$

so

$e^2 = sum_{i=0}^{oo}2^i/(i!)$

then

$2^3sum_{i=0}^{oo}2^i/(i!) = sum_{i=0}^{oo}2^{i+3}/(i!) = 2^3e^2$

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