How do you write $y-6=4/3(x-3)$ in standard form?

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Answer 1 · 2018-07-09T22:40:16

$y=4/3x+2$

The given equation of line: $y-6=4/3(x-3)$ can be rewritten in slope intercept form as follows

$y-6=4/3x-4/3 \cdot3$

$y=4/3x-4+6$

$y=4/3x+2$

Answer 2 · 2018-07-09T22:44:04

$y=4/3x+2$

We are essentially trying to get this equation into slope-intercept form, so the only thing we want on the left is a $y$ .

In our example, we can start by distributing the $4/3$ on the right side to get

$y-6=4/3x-4$

Next, let's add $6$ to both sides to get

$y=4/3x+2$

Now, our equation is in slope-intercept form, $y=mx+b$ .

Hope this helps!

How do you write y-6=4/3(x-3)y-6=4/3(x-3) in standard form?