How do you write $y-5=4(x+2)$ in standard form?

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How do you write $y-5=4(x+2)$ in standard form?

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Answer 1 · 2018-03-31T09:59:33

$4x-y=-13$

Explanation:

$"the equation of a line in "color(blue)"standard form"$ is.

$color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))$

$"where A is a positive integer and B, C are integers"$

$"rearrange "y-5=4(x+2)" into this form"$

$rArry-5=4x+8$

$"subtract y from both sides"$

$cancel(y)cancel(-y)-5=4x-y+8$

$rArr-5=4x-y+8$

$"subtract 8 from both sides"$

$-5-8=4x-ycancel(+8)cancel(-8)$

$rArr4x-y=-13larrcolor(red)"in standard form"$

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How do you write $y-5=4(x+2)$ in standard form?

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How do you write y-5=4(x+2)y-5=4(x+2) in standard form?

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How do you write $y-5=4(x+2)$ in standard form?